Mathematics > Analysis of PDEs
[Submitted on 17 Apr 2018 (v1), last revised 31 Mar 2021 (this version, v2)]
Title:The Hardy--Schrödinger Operator on the Poincaré Ball: Compactness and Multiplicity
View PDFAbstract:Let $\Omega$ be a compact smooth domain containing zero in the Poincaré ball model of the Hyperbolic space $\mathbb{B}^{n}$ ($n \geq 3$) and let $-\Delta_{\mathbb{B}^{n}}$ be the Laplace-Beltrami operator on $\mathbb{B}^{n}$, associated with the metric $g_{\mathbb{B}^{n}}= \frac{4}{(1-|x|^{2})^2}g_{_{\hbox{Eucl}}}$. We consider issues of non-existence, existence, and multiplicity of variational solutions for the borderline Dirichlet problem, \begin{eqnarray*} (E)~ \left\{ \begin{array}{lll} -\Delta_{\mathbb{B}^{n}}u-\gamma{V_2}u -\lambda u&=V_{2^\star(s)}|u|^{2^\star(s)-2}u &\hbox{ in }\Omega\\ \hfill u &=0 & \hbox{ on } \partial \Omega, \end{array} \right. \end{eqnarray*} where $0\leq \gamma \leq \frac{(n-2)^2}{4}$, $0< s <2$, ${2^\star(s)}:=\frac{2(n-s)}{n-2}$ is the corresponding critical Sobolev exponent, $V_{2}$ (resp., $V_{2^\star(s)}$) is a Hardy-type potential (resp., Hardy-Sobolev weight) that is invariant under hyperbolic scaling and which behaves like $\frac{1}{r^{2}}$ (resp., $\frac{1}{r^{s}}$) at the origin. The bulk of this paper is a sharp blow-up analysis on approximate solutions of $(E)$ with bounded but arbitrary high energies. Our analysis leads to existence of positive ground state solutions for $(E)$, whenever $n \geq 4$, $0 \leq \gamma \leq \frac{(n-2)^2}{4}-1$ and $ \lambda > 0$. The latter result also holds true for $n\geq 3$ and $\gamma > \frac{(n-2)^2}{4}-1$ provided the domain has a positive "hyperbolic mass". On the other hand, the same analysis yields that if $\gamma > \frac{(n-2)^2}{4}-1$ and the mass is non vanishing, then there is a surprising stability of regimes where no variational positive solution exists. As for higher energy solutions to $(E)$, we show that there are infinitely many of them provided $n\geq 5$, $0\leq \gamma<\frac{(n-2)^2}{4}-4$ and $ \lambda > \frac{n-2}{n-4} \left(\frac{n(n-4)}{4}-\gamma \right)$.
Submission history
From: Saikat Mazumdar [view email][v1] Tue, 17 Apr 2018 00:17:27 UTC (29 KB)
[v2] Wed, 31 Mar 2021 19:13:51 UTC (49 KB)
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